词语吧>英语词典>exponentiation翻译和用法

exponentiation

n.  取幂,求幂,乘方

计算机

英英释义

noun

  • the process of raising a quantity to some assigned power
      Synonym:involution

    双语例句

    • The hardware architecture is made up of modular controller, modular exponentiation controller, data register, and modular multiplication operation units.
      算法的硬件结构由模乘控制器、模幂控制器、数据寄存器和模乘运算单元构成。
    • Based on analyses of self-randomized modular exponentiation algorithm, a new side-channel atomic strict self-randomized modular exponentiation algorithm is proposed in which a BBS random number generator and the side-channel atomic technology are applied to improve the original algorithm.
      通过对自随机化模幂算法的分析,提出将BBS随机数发生器和侧信道原子化技术应用于改进的算法中,得到侧信道原子化的严格自随机化模幂算法。
    • Notice how here the fact that we added exponentiation to the system has been done in effectively six lines of code with zero surface change to the rest of the Calc class.
      注意,这里我们只使用6行代码就有效地向系统添加了求幂运算,同时没有对Calc类进行任何表面更改。
    • The window method is used to significantly reduce the number of modular multiplications needed for completing the modular exponentiation.
      在设计中还采用了窗口法减少模幂运算过程中所需进行的模乘运算次数,大大提高了处理速度。
    • Modular exponentiation of larger-number has universal application in cryptography, and it is the base operation in most public-key cryptography algorithms.
      大数模幂在密码学领域有广泛的应用,它是公钥密码的基础。
    • A new fast dynamic combined modular exponentiation multiplication is presented.
      提出了一种新的动态组合RSA算法。
    • First, computers have circuits for performing arithmetic operations, such as: addition, subtraction, division, multiplication and exponentiation.
      第一,计算机具有进行加、、、及取幂等各种算术运算的电路。
    • In this case, the exponentiation operator is another form of binary operator so the existing BinaryOp case class serves.
      在本例中,求幂运算符是另一种形式的二进制运算符,所以使用现有BinaryOpcase类就可以。
    • A modular exponentiation for very large integers is one of the most common fundamental operations in many public-key cryptosystems.
      模乘幂运算是公钥密码体制中最常用的基本运算,提高其运算速度可有效地提高公钥密码算法的加解密效率。
    • Running this code verifies that exponentiation works ( modulo the bug I mentioned earlier), so half of the battle is now complete.
      运行这段代码确保可以求幂(忽略我之前提到的bug),这样就完成了一半的工作。